((z^2)/6)-(3z/2)-27=0

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Solution for ((z^2)/6)-(3z/2)-27=0 equation: 


z in (-oo:+oo)

(z^2)/6-((3*z)/2)-27 = 0

(z^2)/6+(-3/2)*z-27 = 0

1/6*z^2-3/2*z-27 = 0

DELTA = (-3/2)^2-(-27*1/6*4)

DELTA = 81/4

DELTA > 0

z = ((81/4)^(1/2)+3/2)/(1/6*2) or z = (3/2-(81/4)^(1/2))/(1/6*2)

z = 18 or z = -9

z in { -9, 18 }

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